4(3x+5)=12x+20^

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Solution for 4(3x+5)=12x+20^ equation: 



4(3x+5)=12x+20^

We move all terms to the left:

4(3x+5)-(12x+20^)=0

We multiply parentheses

12x-(12x+20^)+20=0

We get rid of parentheses

12x-12x+20-20^=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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